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MySQL | SUBSTRING_INDEX method

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MySQL
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String
schedule Mar 10, 2022
Last updated
local_offer MySQL
Tags

MySQL's SUBSTRING_INDEX(~) method returns the substring before the count occurrence of a particular delimiter delim in the input source string.

Parameters

1. str | string

The string to return substring from.

2. delim | string

The string that should serve as the delimiter.

The search for delim in the string str is case-sensitive.

3. count | integer

Positive integer: return the substring left of the count occurrence of the delimiter (counting from left).

Negative integer: return the substring right of the count occurrence of the delimiter (counting from the right).

Return value

Case

Return value

The source string str

delim not found in str count times

Substring left of the count occurrence of the delimiter (counting from left)

delim found in str count times (positive count)

Substring right of the count occurrence of the delimiter (counting from right)

delim found in str count times (negative count)

Examples

Basic usage

To return the substring left of the first occurrence of 'sky':

SELECT SUBSTRING_INDEX('www.skytowner.com', 'sky', 1);
+------------------------------------------------+
| SUBSTRING_INDEX('www.skytowner.com', 'sky', 1) |
+------------------------------------------------+
| www. |
+------------------------------------------------+

To return the substring left of the first occurrence of 'sky':

SELECT SUBSTRING_INDEX('www.skytowner.com', 'SKY', 1);
+------------------------------------------------+
| SUBSTRING_INDEX('www.skytowner.com', 'SKY', 1) |
+------------------------------------------------+
| www.skytowner.com |
+------------------------------------------------+

No match is found when there is a case-insensitive match between delimiter and source string:

Count parameter

To return the substring left of the 2nd '.' (counting from the left):

SELECT SUBSTRING_INDEX('www.skytowner.com', '.', 2);
+----------------------------------------------+
| SUBSTRING_INDEX('www.skytowner.com', '.', 2) |
+----------------------------------------------+
| www.skytowner |
+----------------------------------------------+

To return the substring right of the 2nd '.' (counting from the right):

SELECT SUBSTRING_INDEX('www.skytowner.com', '.', -2);
+-----------------------------------------------+
| SUBSTRING_INDEX('www.skytowner.com', '.', -2) |
+-----------------------------------------------+
| skytowner.com |
+-----------------------------------------------+
robocat
Published by Arthur Yanagisawa
Edited by 0 others
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