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MySQL | POSITION method

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schedule Jul 1, 2022
Last updated
local_offer MySQL
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MySQL's POSITION(~) method returns the position of the first occurrence of a substring in the source string.

Syntax

POSITION(substr IN str);

Parameters

1. substr | string

The substring we are trying to find in str.

2. str | string

The source string we are trying to locate the substring in.

Return value

Case

Return value

Position of first occurrence of substr

If the substr exists in str

0

If the substr does NOT exist in str

Examples

Consider the following table about some students:

student_id

fname

lname

day_enrolled

age

username

1

Sky

Towner

2015-12-03

17

stowner1

2

Ben

Davis

2016-04-20

19

bdavis2

3

Travis

Apple

2018-08-14

18

tapple3

4

Arthur

David

2016-04-01

16

adavid4

5

Benjamin

Town

2014-01-01

17

btown5

The above sample table can be created using the code here.

Basic usage

To find the position of first occurrence of 'd' in usernames:

SELECT username, POSITION('d' IN username) AS 'Position of d'
FROM students;
+----------+---------------+
| username | Position of d |
+----------+---------------+
| stowner1 | 0 |
| bdavis2 | 2 |
| tapple3 | 0 |
| adavid4 | 2 |
| btown5 | 0 |
+----------+---------------+

Note that counting of position starts at 1 in MySQL unlike some other programming languages that start at 0.

Case sensitivity

The search is NOT case-sensitive:

SELECT username, POSITION('D' IN username) AS 'Position of D'
FROM students;
+----------+---------------+
| username | Position of D |
+----------+---------------+
| stowner1 | 0 |
| bdavis2 | 2 |
| tapple3 | 0 |
| adavid4 | 2 |
| btown5 | 0 |
+----------+---------------+

Even when using 'D' (capital letter) as our substring, we still find matches in usernames bdavis and adavid4.

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Published by Arthur Yanagisawa
Edited by 0 others
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