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Extracting numbers from column in Pandas DataFrame

schedule Aug 12, 2023
Last updated
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Consider the following DataFrame:

import pandas as pd
import numpy as np
df = pd.DataFrame({'A':['a10','a 10','09','0',np.nan]})
df
A
0 a10
1 a 10
2 09
3 0
4 NaN

To extract numbers from column A:

df['A'].str.extract('(\d+)') # returns a DataFrame
0
0 10
1 10
2 09
3 0
4 NaN

Here, the argument string is a regex:

  • \d+ represents a number

  • () indicates the group you want to extract

If you wanted a Series instead of a DataFrame:

df['A'].str.extract('(\d+)', expand=False) # returns a Series
0 10
1 10
2 09
3 0
4 NaN
Name: A, dtype: object
robocat
Published by Isshin Inada
Edited by 0 others
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