**Pandas**

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**Common questions**

# Difference between None and NaN in Pandas

*schedule*Aug 11, 2023

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The distinction between `None`

and `NaN`

in Pandas is subtle:

`None`

represents a missing entry, but its type is not numeric. This means that any column (Series) that contains a`None`

cannot be of type numeric (e.g.`int`

and`float`

).`NaN`

, which stands for not-a-number, is a numeric type. This means that`NaN`

can appear in columns of type`int`

and`float`

.

# Numeric Series

Consider a Series initialised with `None`

:

```
s = pd.Series([3,None])s
0 3.01 NaNdtype: float64
```

The resulting Series contains a `NaN`

instead of `None`

. This is because Pandas automatically converted `None`

to `NaN`

given that the other value (`3`

) is a numeric, which then allows the column type to be `float64`

. If `None`

was not casted into `NaN`

, then the column type would end up as `object`

, which is inaccurate and makes certain operations in Pandas less performant.

Let us create a Series with `NaN`

:

```
import numpy as nps = pd.Series([3,np.nan])s
0 3.01 NaNdtype: float64
```

As you would expect, the result is identical, and the only difference is that Pandas did not need to perform any casting from `None`

to `NaN`

since `NaN`

was directly given.

# Non-numeric Series

We have seen that `None`

is automatically converted into `NaN`

when the Series type is numeric.

For non-numeric Series, `None`

does not get casted to `NaN`

:

```
s = pd.Series(["3",None])s
0 31 Nonedtype: object
```

In comparison, creating a Series with `NaN`

:

```
s = pd.Series(["3",np.nan])s
0 31 NaNdtype: object
```

Here, `NaN`

simply remains a `NaN`

since numeric values are allowed in a Series that holds other data types (a `string`

in this case). Note that since the Series holds mixed-types, the dtype is `object`

.

# Arithmetics

The fact that `None`

is not a numeric type, whereas `NaN`

is, has consequences when performing arithmetics.

When performing arithmetics with `None`

:

```
None + 5
TypeError: unsupported operand type(s) for +: 'NoneType' and 'int'
```

Here, we get an error because a summation between a non-numeric type (`None`

) and a number is not defined.

In contrast:

```
np.nan + 5
nan
```

Here, no error is thrown and instead, a `NaN`

is returned. Any arithmetic operation that involves a `NaN`

will result in another `NaN`

.

# Equality comparison

Another difference in how `None`

and `NaN`

behave is in equality comparison.

Equating `None`

will result in `True`

:

```
None == None
True
```

Equating `NaN`

will result in `False`

:

```
np.nan == np.nan
False
```

As a side note, equating anything with `NaN`

will result in `False`

:

```
np.nan == None
False
```

To check for values that are `NaN`

, instead of using `==`

, opt to use `isna(~)`

:

```
pd.isna(np.nan)
True
```

Note that `isna(~)`

returns `True`

for `None`

as well:

```
pd.isna(None)
True
```