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Python Dictionary | pop method

schedule Aug 12, 2023
Last updated
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Python
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Python's dict.pop(~) method removes the key/value pair at the given key from a dictionary and then returns the removed value.

Parameters

1. key | any type

The key of the key/value pair to be removed from the dictionary.

2. default | any type | optional

The default value to return if the specified key is not present in the dictionary.

Return value

Case

Return value

key is present in dictionary

value corresponding to key

key is not present and default value provided

default value

key is not present and no default value provided

KeyError

Examples

Basic usage

To remove the key/value pair for "Emma" and return its corresponding value:

test_scores = {"Mike": 3, "Adam": 5,"Emma": 7}
print("Emma's score was ", test_scores.pop("Emma"))
print("The remaining dictionary is ", test_scores)
Emma's score was 7
The remaining dictionary is {'Mike': 3, 'Adam': 5}

We remove the key "Emma" from test_scores dictionary and then return the corresponding value of 7.

Default parameter

To remove the key/value pair for "Kate" and return the value:

test_scores = {"Mike": 3, "Adam": 5,"Emma": 7}
print("Kate's score was ", test_scores.pop("Kate", "N/A"))
Kate's score was N/A

The default argument "N/A" is returned as "Kate" was not found in dictionary test_scores.

KeyError

If we do not provide a default argument, and the key does not exist in the dictionary, KeyError is raised:

test_scores = {"Mike": 3, "Adam": 5,"Emma": 7}
print("Kate's score was ", test_scores.pop("Kate"))
KeyError: 'Kate'
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Published by Isshin Inada
Edited by 0 others
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