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# MySQL | IN

schedule Aug 10, 2023
Last updated
local_offer
MySQL
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MySQL's `IN` operator allows you to combine multiple `OR` conditions elegantly. If a value is equal to any of the values provided in the `IN` list it returns `1` (true), otherwise it returns `0` (false).

# Syntax

``` SELECT value IN (value1, value2, value3, ...);SELECT column_nameFROM table_nameWHERE column_name IN (value1, value2, ...); ```

# Examples

Consider the following table about some students:

student_id

fname

lname

day_enrolled

age

1

Sky

Towner

2015-12-03

17

stowner1

2

Ben

Davis

2016-04-20

19

bdavis2

3

Travis

Apple

2018-08-14

18

tapple3

4

Arthur

David

2016-04-01

16

5

Benjamin

Town

2014-01-01

17

btown5

The above sample table can be created using the code here.

## Basic usage

To check whether `4` is one of the listed winning numbers:

``` SELECT 4 IN (0, 6, 10, 14); +---------------------+| 4 IN (0, 6, 10, 14) |+---------------------+| 0 |+---------------------+ ```

Unfortunately `4` is not one of the winning numbers `0`, `6`, `10` or `14`.

To retrieve students who are either `16`, `17` or `18` years old:

``` SELECT *FROM students WHERE age IN (16, 17, 18); +------------+----------+--------+--------------+------+----------+| student_id | fname | lname | day_enrolled | age | username |+------------+----------+--------+--------------+------+----------+| 1 | Sky | Towner | 2015-12-03 | 17 | stowner1 || 3 | Travis | Apple | 2018-08-14 | 18 | tapple3 || 4 | Arthur | David | 2016-04-01 | 16 | adavid4 || 5 | Benjamin | Town | 2014-01-01 | 17 | btown5 |+------------+----------+--------+--------------+------+----------+ ```

All students except for Ben Davis who is `19` are returned.

Edited by 0 others
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