search
Search
Publish
menu
menu search toc more_vert
Robocat
Guest 0reps
Thanks for the thanks!
close
Comments
Log in or sign up
Cancel
Post
account_circle
Profile
exit_to_app
Sign out
help Ask a question
Share on Twitter
search
keyboard_voice
close
Searching Tips
Search for a recipe: "Creating a table in MySQL"
Search for an API documentation: "@append"
Search for code: "!dataframe"
Apply a tag filter: "#python"
Useful Shortcuts
/ to open search panel
Esc to close search panel
to navigate between search results
d to clear all current filters
Enter to expand content preview
icon_star
Doc Search
icon_star
Code Search Beta
SORRY NOTHING FOUND!
mic
Start speaking...
Voice search is only supported in Safari and Chrome.
Navigate to
A
A
share
thumb_up_alt
bookmark
arrow_backShare
Twitter
Facebook

Beautiful Soup | previous_sibling property

Programming
chevron_right
Python
chevron_right
Beautiful Soup
chevron_right
Documentation
schedule Mar 10, 2022
Last updated
local_offer PythonBeautiful Soup
Tags
tocTable of Contents
expand_more

In Beautiful Soup, the previous_sibling property of a tag or a string returns the previous tag or string under the same parent.

Examples

Basic usage

Consider the following HTML document:

my_html = "<p><b>Alex</b><i>is great</i></p>"
soup = BeautifulSoup(my_html)

Let's get the previous_sibling of <i>is great</i>:

i_tag = soup.find("i")
i_tag.previous_sibling
<b>Alex</b>

This tell us that the previous node of <i>is great</i> is <b>Alex</b>, which we know is true since <b>Alex</b> is the previous element under the same p tag.

If the previous node does not exist, then a None is returned:

i_tag = soup.find("i")
i_tag.previous_sibling.previous_sibling
None

Unexpected behaviour

Consider the following HTML document:

my_html = """
   <div>
      <p>Alex</p>
      <p id="bob">Bob</p>
   </div>
"""
soup = BeautifulSoup(my_html)

Let's get the previous_sibling of <p id="bob">Bob</p>:

p_bob = soup.find(id="bob")
p_bob.previous_sibling
'\n'

The result may be surprising for those who expected to see <p>Bob</p>. Such a result arises because there is a new line character \n between <b>Alex</b> and <b>Bob</b>. To get to Alex, then, you would need to call the previous_sibling twice:

p_bob = soup.find(id="bob")
p_bob.previous_sibling.previous_sibling
<p>Bob</p>

If you just wanted to access the previous element, then the better alternative would be to call the find_previous_sibling() method:

p_bob = soup.find(id="bob")
<p>Alex</p>
robocat
Published by Isshin Inada
Edited by 0 others
Did you find this page useful?
thumb_up
thumb_down
Ask a question or leave a feedback...