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PySpark SQL Functions | translate method

schedule Aug 12, 2023
Last updated
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PySpark SQL Functions' translate(~) method replaces the specified characters by the desired characters.

Parameters

1. srcCol | string or Column

The column to perform the operation on.

2. matching | string

The characters to be replaced.

3. replace | string

The characters to replace matching.

Return Value

A new PySpark Column.

Examples

Consider the following PySpark DataFrame:

df = spark.createDataFrame([["Alex", 20], ["Bob", 30], ["Cathy", 40]], ["name", "age"])
df.show()
+-----+---+
| name|age|
+-----+---+
| Alex| 20|
| Bob| 30|
|Cathy| 40|
+-----+---+

Replacing characters in PySpark Column

Suppose we wanted to make the following character replacements:

A -> #
e -> @
o -> %

We can perform these character replacements using the translate(~) method:

import pyspark.sql.functions as F
df.select(F.translate("name", "Aeo", "#@%")).show()
+-------------------------+
|translate(name, Aeo, #@%)|
+-------------------------+
| #l@x|
| B%b|
| Cathy|
+-------------------------+

Note that we can obtain a new PySpark DataFrame with the translated column using the withColumn(~) method:

df_new = df.withColumn("name", F.translate("name", "Aeo", "#@%"))
df_new.show()
+-----+---+
| name|age|
+-----+---+
| #l@x| 20|
| B%b| 30|
|Cathy| 40|
+-----+---+

Finally, note that specifying less characters for the replace parameter will result in the removal of the corresponding characters in matching:

df.select(F.translate("name", "Aeo", "#")).show()
+-----------------------+
|translate(name, Aeo, #)|
+-----------------------+
| #lx|
| Bb|
| Cathy|
+-----------------------+

Here, the characters e and o are removed, while A is replaced by #.

robocat
Published by Isshin Inada
Edited by 0 others
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