student_id	fname	lname	day_enrolled	age	username
1	Sky	Towner	2015-12-03	17	stowner1
2	Ben	Davis	2016-04-20	19	bdavis2
3	Travis	Apple	2018-08-14	18	tapple3
4	Arthur	David	2016-04-01	16	adavid4
5	Benjamin	Town	2014-01-01	17	btown5

The above sample table can be created using the code here.

Examples

Returning the average age of students:


        
        
            
                
                
                    SELECT AVG(age) AS "Average Age"
FROM students;
                
            
            +-------------+
| Average Age |
+-------------+
|     17.4000 |
+-------------+
1 row in set (0.00 sec)

Filter for only students older than average age:


        
        
            
                
                
                    SELECT *
FROM students
WHERE age > (SELECT AVG(age) FROM students);
                
            
            +------------+--------+-------+--------------+------+----------+
| student_id | fname  | lname | day_enrolled | age  | username |
+------------+--------+-------+--------------+------+----------+
|          2 | Ben    | Davis | 2016-04-20   |   19 | bdavis2  |
|          3 | Travis | Apple | 2018-08-14   |   18 | tapple3  |
+------------+--------+-------+--------------+------+----------+
2 rows in set (0.01 sec)

Published by Arthur Yanagisawa

Edited by 0 others

Did you find this page useful?

thumb_up

thumb_down

Comment

Citation

Ask a question or leave a feedback...

Official MySQL Documentation

https://dev.mysql.com/doc/refman/8.0/en/group-by-functions.html#function_avg

thumb_up

thumb_down

chat_bubble_outline

settings

Enjoy our search

Hit / to insta-search docs and recipes!