chevron_left
Probability Theory
0
0
0
new
Conditional Probability
Probability and Statistics
chevron_rightProbability Theory
schedule Mar 9, 2022
Last updated tocTable of Contents
expand_more Let $A$ and $B$ be any two mutually exclusive events defined over $S$. Then the following is true:
$$\mathbb{P}(B|A)=\frac{\mathbb{P}(B\cap{A})}{\mathbb{P}(A)}$$
$\mathbb{P}(B|A)$ is read as the "probability of $B$ given that $A$ occurred".
Example
Question. The probability that a product is defective is 0.5. The probability that a product is defective and a customer complains is 0.2. What is the probability that a customer complains given that the product is defective?
Solution. Let A be the event that the product is defective. Let B denote the event that a customer complains. Then probability that a customer complains given that the product is defective is:
$$\mathbb{P}(B|A)=\frac{\mathbb{P}(B\cap{A})}{\mathbb{P}(A)}
=\frac{0.2}{0.5}
=0.4$$
Published by Isshin Inada
Edited by 0 others
Did you find this page useful?
Ask a question or leave a feedback...